from a height of 1.5m a 2.0kg block slides down an incline which is 2.5m long and out onto the level floor. how far does it slide horizontally? muse of k is 0.32
just a note: that's "mu sub-k," not "muse of k"
µk
Your class must be an oral presentation, if you never saw it written.
Anyway, convert mgh=2.0 * 9.8 * 1.5
to KE, 1/2 * 2.0 * v^2
Using that v, and the frictional force of deceleration, figure the distance
v = at =0 to get the time, then the distance is
s = v0*t + 1/2 at^2