FIND THE PERCENTAGE BY VOLUME COMPOSITION OF A VINEGAR SOLUTION CONTAINING 10cm (TO THE POWER OF 3) OF ACETIC ACID AND 190 (TO THE POWER OF 3)OF H2O
45%
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To calculate the percentage by volume composition of a vinegar solution, you need to determine the volume of acetic acid and the volume of water in the solution.
Given:
- Volume of acetic acid (CH3COOH) = 10 cm³
- Volume of water (H2O) = 190 cm³
Step 1: Calculate the total volume of the vinegar solution.
Total volume = Volume of acetic acid + Volume of water
Total volume = 10 cm³ + 190 cm³
Total volume = 200 cm³
Step 2: Calculate the percentage by volume of acetic acid.
% volume of acetic acid = (Volume of acetic acid / Total volume) x 100
% volume of acetic acid = (10 cm³ / 200 cm³) x 100
% volume of acetic acid = 5%
Step 3: Calculate the percentage by volume of water.
% volume of water = (Volume of water / Total volume) x 100
% volume of water = (190 cm³ / 200 cm³) x 100
% volume of water = 95%
Therefore, the vinegar solution contains 5% acetic acid and 95% water by volume.
You don't give the density of the solution so I have no way of knowing what the final volume. You also don't give any units for the 190^3 for water. If we assume units are cc If we assume the volumes are additive (and you can make that assumption since the volume of water is so large compared to the H2O) then you have acetic solution (10^3) = 1000 cc and water of (190^3) = 6.859E6 cc.
Total volume is 6.859E6 cc + 1000 cc = 6.86E6 cc.
Then % by volume = (1000/6.86E6)*100 = ?