A bullet is fired horizontally from a height of 4.9 m with a velocity of 680 m/s. How far

away does the bullet land?
A) 680 m
B) 340 m
C) 1360 m
D) 170 m
E) 800 m

you need to solve for time first:

d=Vot + 1/2at^2 use g for acceleration

4.9=0+1/2(9.8)t^2
4.9= 4.9 t^2
t^2= 4.9/4.9
t^2=1
t= sqrt(1)=1

Now that you have t you can solve for d:
d=vt
d=(680m/s)(1)
d=680m

To find the distance the bullet lands, we need to determine the time it takes for the bullet to hit the ground.

Since the bullet is fired horizontally, there is no vertical component to its velocity. Therefore, the bullet will fall under the influence of gravity just like any other object and follow a parabolic path.

We can use the equation for vertical motion to determine the time it takes for the bullet to fall.

The equation for vertical motion is:

y = v*t + (1/2)*g*t^2

Where:
y = vertical displacement (in this case, the initial height of 4.9 m)
v = initial vertical velocity (0 m/s since the bullet is fired horizontally)
t = time
g = acceleration due to gravity (approximately 9.8 m/s^2)

Plugging in the values:

4.9 = 0*t + (1/2)*9.8*t^2
4.9 = 4.9*t^2
t^2 = 1

Taking the square root of both sides:

t = ±1

Since time cannot be negative, we take the positive solution:

t = 1 s

So it takes 1 second for the bullet to hit the ground.

Now, we can find the distance the bullet lands by using the formula:

d = v*t

Plugging in the values:

d = 680 m/s * 1 s
d = 680 m

Therefore, the bullet lands 680 m away.

The correct answer is A) 680 m.

To find the horizontal distance the bullet lands, we need to find the time it takes for the bullet to travel and then use that time to find the distance.

First, let's find the time of flight. Since the bullet is fired horizontally, there is no initial vertical velocity, and thus the only acceleration acting on the bullet is the acceleration due to gravity.

The height of the bullet is given as 4.9 m. We can use the formula for the vertical motion under gravity to find the time taken to reach the ground:

Height = (1/2) * acceleration * time^2

Simplifying the equation for time:

4.9 m = (1/2) * 9.8 m/s^2 * time^2
4.9 m = 4.9 m/s^2 * time^2
time^2 = 1
time = 1 s

Now that we have the time of flight, we can use it to find the horizontal distance traveled by the bullet. The horizontal distance is given by the equation:

Distance = velocity * time

Plugging in the values:

Distance = 680 m/s * 1 s
Distance = 680 m

Therefore, the bullet lands 680 meters away from the firing point. The answer is (A) 680 m.