You measure a uniform electric field of 13.3 x 10^3 N/C between two equipotential surfaces. One surface is at a potential of 1543 V and the other is at 951 V. What is the separation between the two surfaces?

How would I solve this?...What equations would I use?

Thanks!

To solve this problem, you can use the equation for the electric field between two parallel plates, which is given by:

E = V / d,

where E is the electric field, V is the potential difference between the two plates, and d is the separation between the plates.

In this case, you are given the electric field, E = 13.3 x 10^3 N/C, and the potential difference, V = (1543 - 951) V.

To find the separation, you can rearrange the equation and solve for d:

d = V / E.

Now, substitute the given values into the equation:

d = (1543 - 951) V / (13.3 x 10^3 N/C).

Calculating this, you will get the separation, d, in meters.