A student expends 9.6W of power lifting a textbook 0.50m in 3.0s with a constant velocity. How much work is done?
just watch the units:
9.6 J/s * 3.0s = 28.8 J
The height lifted is irrelevant, since that will just be part of the work.
9.6 J/s * 3.0s = 28.8 J
The height lifted is irrelevant, since that will just be part of the work.
To find the work done, we need to use the formula:
Work = power x time
Given that the power expended is 9.6W and the time is 3.0s, we can substitute these values into the formula to find the work done:
Work = 9.6W x 3.0s
Multiplying the power and time together:
Work = 28.8 Joules
Therefore, the work done in lifting the textbook is 28.8 Joules.