A student expends 9.6W of power lifting a textbook 0.50m in 3.0s with a constant velocity. How much work is done?

just watch the units:

9.6 J/s * 3.0s = 28.8 J

The height lifted is irrelevant, since that will just be part of the work.

9.6 J/s * 3.0s = 28.8 J

The height lifted is irrelevant, since that will just be part of the work.

To find the work done, we need to use the formula:

Work = power x time

Given that the power expended is 9.6W and the time is 3.0s, we can substitute these values into the formula to find the work done:

Work = 9.6W x 3.0s

Multiplying the power and time together:

Work = 28.8 Joules

Therefore, the work done in lifting the textbook is 28.8 Joules.