The equilibrium constant of the reaction CH3COOH (l)+C2H5OH (l)=CH3COOC2H5+H2O is 4.if one mole of each of acetic acid and ethyl alcohol are heated in presence of little concentrated H2SO4 at equilibrium the amount of ester present is?

It comes out 2 and 2/3 and we have to take 2/3

Because (1-2) would be negative and concentration cannot be negative

To find the amount of ester present at equilibrium, we need to calculate the equilibrium concentrations of the reactants and products. The equilibrium constant (K) for a reaction is defined as the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of their respective stoichiometric coefficients.

In this reaction, the stoichiometric coefficients are as follows:

CH3COOH (l) + C2H5OH (l) ⇌ CH3COOC2H5 (l) + H2O

From the given information, the equilibrium constant (K) is 4. This means that at equilibrium, the concentration of the products, CH3COOC2H5 and H2O, divided by the concentration of the reactants, CH3COOH and C2H5OH, will be 4.

Let's assume that the initial concentrations of CH3COOH and C2H5OH are both 1 mole.

At equilibrium, let's say x moles of CH3COOC2H5 and H2O are formed.

So the equilibrium concentrations will be:

[CH3COOH] = (1 - x)
[C2H5OH] = (1 - x)
[CH3COOC2H5] = x
[H2O] = x

Using the given equilibrium constant expression:

K = [CH3COOC2H5][H2O] / [CH3COOH][C2H5OH]

Substituting the equilibrium concentrations:

4 = (x)(x) / ((1 - x)(1 - x))

We can rearrange the equation and solve for x:

4(1 - x)(1 - x) = x^2

Expanding the equation:

4 - 4x - 4x + 4x^2 = x^2

Simplifying:

4 - 8x + 4x^2 = x^2

Rearranging the equation:

3x^2 + 8x - 4 = 0

Now we can solve this quadratic equation to find the value of x.

why not 2

I've shortened the equation. HAc is acetic acid, RCH2OH is the alcohol and RCOOR is the ester.

..........HAc + RCH2OH --> RCOOR + H2O
I.........1.0....1.0........0.......0
C..........-x.....x.........x.......x
E.........1.0-x..1.0-x......x.......x

Substitute the E line into Kc and solve.

Ester present is 2 moles, because first of all,

4=x^2/(1-x)(1-x) solve it and it will turn out to be this
3x^2-8x+4
x=2

so the ester is 2 =