Calculate the pH of a solution obtained by adding 20 mL of .2M KOH to 480 mL to .02M isoelectric glycine
I believe you can use the Henderson-Hasselbalch equation for this
pH = pKa + log (base)/(acid)
You have the zwitterion at the isoelectric point and you are taking away the H^+ from the NH3^+ group.
Acid + OH ==> base + H2O
etc.
You have 480 x 0.02M = 9.6 millimols to start.
You add 20 x 0.2 = 4 mmols OH.
You produce 4 mmols of the base.
I would use pK2 for pKa.
I get about 9.6 using 9.76 for pK2.