The probability that Roberto wins is 1/3 the probability that Roberto loses. What is the probability that Roberto loses?
Roberto Wins- 1/4
Roberto Loses- 3/4
Well, if the probability that Roberto wins is 1/3 the probability that he loses, then we can assume that the probability of him losing is 3/3. So, Roberto's chances of losing are absolutely certain, which is quite unfortunate for him. Looks like he might want to work on his luck!
Let's assume the probability of Roberto losing is x.
According to the given information, the probability of Roberto winning is 1/3 times the probability of Roberto losing, which can be expressed as:
1/3 * x
Since the sum of the probabilities of winning and losing is always equal to 1, we can write the following equation:
x + 1/3 * x = 1
Multiplying both sides of the equation by 3 to eliminate the fraction:
3x + x = 3
Combining like terms:
4x = 3
Dividing both sides of the equation by 4:
x = 3/4
So, the probability that Roberto loses is 3/4.
To find the probability that Roberto loses, we can set up an equation based on the given information.
Let's assume the probability that Roberto wins is represented by the variable "P(Roberto wins)" and the probability that Roberto loses is represented by the variable "P(Roberto loses)".
According to the given information, the probability that Roberto wins is 1/3 the probability that Roberto loses. Therefore, we can write the equation as:
P(Roberto wins) = (1/3) * P(Roberto loses)
Now, let's solve for the probability that Roberto loses:
P(Roberto loses) = P(Roberto wins) / (1/3)
Since we don't have a specific value for P(Roberto wins), we cannot calculate the exact probability that Roberto loses. However, we can still simplify the expression:
P(Roberto loses) = (1/3) * P(Roberto wins)
Therefore, the probability that Roberto loses is (1/3) times the probability that Roberto wins.