A cylinder of gas contains 96.0 g of oxygen gas, O2. If the volume of the cylinder is 9.00 liter and at 25.0 degrees C. What is the pressure of O2 in the cylinder?
Use PV = nRT and solve for P.
n for O2 = grams O2/molar mass O2
To calculate the pressure of O2 in the cylinder, we can use the Ideal Gas Law equation:
PV = nRT
Where:
P = Pressure
V = Volume
n = number of moles
R = ideal gas constant
T = Temperature
First, we need to calculate the number of moles (n) of oxygen gas (O2) using its molar mass (32.00 g/mol).
n = mass / molar mass
n = 96.0 g / 32.00 g/mol
n = 3.0 mol
Next, we need to convert the temperature from Celsius to Kelvin using the equation:
T(K) = T(C) + 273.15
T(K) = 25.0°C + 273.15
T(K) = 298.15 K
Now, we can substitute the values into the Ideal Gas Law equation to solve for pressure (P).
P * 9.00 L = 3.0 mol * 0.0821 L·atm/mol·K * 298.15 K
Simplifying the equation:
P * 9.00 L = 73.59 L·atm
Dividing both sides of the equation by 9.00 L:
P = 73.59 L·atm / 9.00 L
P ≈ 8.18 atm
Therefore, the pressure of O2 in the cylinder is approximately 8.18 atm.
To find the pressure of O2 in the cylinder, we can use the ideal gas law equation, which states that:
PV = nRT
Where:
- P is the pressure of the gas.
- V is the volume of the gas.
- n is the number of moles of the gas.
- R is the ideal gas constant.
- T is the temperature of the gas in Kelvin.
First, let's convert the given temperature from degrees Celsius to Kelvin. The formula to convert Celsius to Kelvin is:
K = °C + 273.15
So, the given temperature of 25.0 degrees Celsius is equal to 25.0 + 273.15 = 298.15 Kelvin.
Next, let's determine the number of moles of oxygen gas in the cylinder. We can use the molar mass of oxygen gas (O2), which is 32.00 g/mol.
moles of O2 = mass of O2 / molar mass of O2
moles of O2 = 96.0 g / 32.00 g/mol
moles of O2 = 3.00 mol
Now that we have all the necessary values, we can substitute them into the ideal gas law equation to solve for the pressure (P):
P * V = n * R * T
Rearranging the equation to solve for P:
P = (n * R * T) / V
Substituting in the values:
P = (3.00 mol * 0.0821 L·atm/mol·K * 298.15 K) / 9.00 L
Calculating this expression:
P = 7.95 atm
Therefore, the pressure of O2 in the cylinder is approximately 7.95 atm.