A flowerpot falls from a window sill 37.7 m

above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s2 .

Can you tell me the steps and why?

***FORGOT TO ASK

How much time does a passerby on the side-
walk below have to move out of the way before
the flowerpot hits the ground?
Answer in units of s

explain please?

For the velocity, equation PE and KE.

PE=KE
mgh = (1/2)mv²
and solve for v.
(both g and h are negative, y is positive upwards)

For time, use
y=vi*t+(1/2)at²
for vi=0, equation simplifies to
y=(1/2)at²
(Notice that both y and g are negative)

To find the velocity of the flowerpot when it strikes the ground, we can use the equation of motion that relates displacement, initial velocity, time, and acceleration.

The equation to use in this case is:

v^2 = u^2 + 2as

Where:
v = final velocity (what we need to find)
u = initial velocity (0 since the flowerpot starts from rest)
a = acceleration due to gravity (-9.81 m/s^2 since it acts in the downward direction)
s = distance fallen (37.7 m)

Step 1: Identify the given values:
a = -9.81 m/s^2
s = 37.7 m
u = 0 m/s (initial velocity)

Step 2: Plug in the values into the equation:
v^2 = 0^2 + 2*(-9.81)*37.7

Step 3: Simplify and solve:
v^2 = -2*(-9.81)*37.7
v^2 = 2*(9.81)*(37.7)
v^2 = 2*369.6577
v^2 ≈ 739.3154

Step 4: Take the square root to find the positive value of velocity:
v ≈ √739.3154
v ≈ 27.175 m/s (rounded to three decimal places)

Therefore, the velocity of the flowerpot when it strikes the ground is approximately 27.175 m/s.

Note: The negative acceleration due to gravity is accounted for by using the negative value for 'a' in the equation, which ultimately results in a positive value for 'v'.