Two point charges q1 = +5.6 10-8 C and q2 = -5.7 10-8 C.

|-----q2
|
|
|
q1----A----------B

from the q2 to A is 10cm
from the q1 to A is 5cm
from A to B is 10 cm


(a) Find the potential at A.
(b) Find the potential at B.
(c) Find the potential difference.

To find the potential at a point due to multiple point charges, you need to consider the contribution of each charge individually and then sum them up.

(a) To find the potential at point A, let's consider the contribution from each charge separately:

Potential due to q1 at A:
The formula to calculate the electric potential due to a point charge is given by V = k * q / r, where V is the potential, k is Coulomb's constant (approximately 9 × 10^9 N m^2/C^2), q is the charge, and r is the distance between the charge and the point where you want to find the potential.

Given that q1 = +5.6 × 10^(-8) C and the distance from q1 to A is 5 cm = 0.05 m, we can calculate the potential due to q1 at A:

V1 = (9 × 10^9 N m^2/C^2) * (5.6 × 10^(-8) C) / (0.05 m)

(b) To find the potential at point B, we repeat the same procedure for q1:

Potential due to q1 at B:
The distance from q1 to B is equal to the distance from q1 to A plus the distance from A to B, which is 0.05 m + 0.1 m = 0.15 m. Using the formula, we can calculate the potential due to q1 at B:

V1 = (9 × 10^9 N m^2/C^2) * (5.6 × 10^(-8) C) / (0.15 m)

(c) To find the potential difference between A and B, we subtract the potential at A from the potential at B:

Potential difference = Vb - Va

Therefore, by calculating the above values individually, we can find the potential at A, potential at B, and the potential difference between A and B.