How many grams of calcium nitrate (molar mass = 164 g) would be formed if 0.500 g of calcium chloride (molar mass = 111 g) were reacted with an excess of silver nitrate (molar mass = 170. g

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  1. 2AgNO3 + CaCl2 ==> Ca(NO3)2 + 2AgCl

    mols CaCl2 = grams/molar mass = ?
    Use the coefficients in the balanced equation to convert mols CaCl2 to mols Ca(NO3)2 (That should be mols CaCl2 x 2 = ?).
    Then g Ca(NO3)2 = mols Ca(NO3)2 x molar mass Ca(NO3)2 = ?

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