physics

a bullet travelling horizontally at a speed of 350 m/!@#$%^&s a board perpendicular to the surface, passes through it and emerges on the other side at a speed of 210 m/s . if the board is 4.00 cm thick, how long does the bullet takes to pass through it ?

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  1. In the case of uniform acceleration,
    distance = average speed * time
    distance = 0.04m
    average velocity = (350+210)/2 m/s
    = 280 m/s
    Time = distance / average speed
    = 0.04/280 s
    = 1.43*10-.4 s

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  2. Vavg = (210+350)/2 = 280 m/s.

    t = d/V = 0.04/280 = 0.00014286 s. =
    142.86 uS.

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    posted by Henry

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