physics

A car traveling at2.24m/s skids and stops in
2.55s determine the skidding distance of car

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  1. Acceleration
    = (vf-vi)/t
    = -2.24/2.55
    = -0.8784 m/s

    Δx = vi*t + (1/2)at²
    =2.24(2.55)+(1/2)(-0.8784)(2.55²)
    = 2.85 m

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