Math

Integrate and simplify the following function:

y= ∫(ln√x/x^2)+x 2^(3-5x^2))dx

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asked by John
  1. well,

    ∫ lnx/x^2 dx = -(lnx + 1)/x
    recall that ln √x = 1/2 lnx

    let u = 3-5x^2 and du=-10x dx
    That gives you
    ∫ -1/10 2^u du
    which is just 2^u / ln u

    Now it's pretty straightforward

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    posted by Steve

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