Math

Show that the derivative of y= cosh-1 (2x-1) is:
dy/dx = √1/(x2-x)

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asked by John
  1. well, we know that d/dx arccosh u = 1/√(u^2-1) du

    So just use the chain rule, and note that

    (2x-1)^2-1 = 4x^2-4x

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    posted by Steve

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