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solve the polynomial y=2x^24x+1 For Further Reading algebra  Reiny, Thursday, May 17, 2007 at 10:34pm I am sure neither your text nor your teacher asked you to "solve the polynomial y=2x^24x+1 " are you graphing the function,
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State the vertex of the graph: y=2x6x+9 ...the 2x is squared. y = 2x^2 6x + 9 The vertex is where the function is a minimum. That would be where dy/dx = 4x 6 = 0 x= 3/2 If you are not familiar with calculus, then rewrite the
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Write an equation for the translation so the graph has the given vertex. 1. y=x vertex (5,0) 2. y=2x vertex (4,3) 3. y=x vertex (p,q) I really have no idea how to even begin these, but I do know the answer to # 2 is
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I need help in finding the vertex of a parabola using an equation in this form: Ax^2 + Bx+C I have a test on this tomorrow. For example: 3x^2 +1x  2 How would I find the vertex in this?
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Identify the vertex and the axis of symmetry for the graph of y=5(x2)^2 + 3. a) vertex (2,3); x = 2 b) vertex (2,3); x = 2 c) vertex (2,3); x = 2 d) vertex (2,3); x = 2 I have no idea how to solve this problem! Please help.
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I cannot for the life of me remember how to do this Find the vertex of the graphs of the functions: Function #1: y=(x4)(x+2) AND Function #2: y=2x^24x+1 Can someone help me get it PLz! OK  to find the vertex of these functions
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Find the Equation. Please check the answers and help. Thanks! 1.) Ellipse with center (0,0), foci on xaxis; x intercepts; major axis of length 12, minor acis of length 8. I got : x^2/144 + y^2/64 = 1 2.) A parabola with vertex
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