MAT221

consider the line 8x-5y=-4
find the equation of the line that is perpendicular to this line and passes through the point (-4,-4)

find the equation of the line that is parallel to this line and passes through the point (-4, -4)

i keep getting different answers on the perpendicular and parallel equations can anybody help?

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asked by Kia
  1. 5 y = 8 x + 4
    y = (8/5) x + 4/5
    so slope is 8/5
    so slope of perpendicular is -5/8
    form is
    y = - 5x/8 + b
    goes through (-4,-4)
    -4 = -5 (-4)/8 + b
    b = -4 - 20/8
    b = -4 - 5/2
    b = -8/2-5/2 = -13/2
    so
    y = - 5 x/8 -13/2
    or
    8y = -5 x - 52

    Now parallel line
    slope = 8/5
    y = 8 x/5 + b
    -4 = -32 /5 + b
    -20/5 = -32 /5 + b
    b = 12 /5
    so
    y = 8 x/5 + 12/5
    or
    5 y = 8 x + 12

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    posted by Damon

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