physics

A referee tosses a coin straight up with a velocity of 5.25 m/s, how high does it go above its point of release? (Hint: How fast is it moving at the maximum height?)

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asked by Jordan
  1. The vertical velocity is 0 at the top

    v = Vi - 9.81 t

    0 = 5.25 - 9.81 t

    t = .535 second to the top

    h = 0 + Vi t - 4.9 t^2

    h = 5.25 (.535) - 4.9 (.535^2)

    h = 1.40 meter

    alternate and faster way:

    (1/2) m v^2 = m g h
    [ conservation of energy ]
    h = v^2/2g = 5.25^2/19.6 = 1.40 meter

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    posted by Damon

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