Physics

A 2.73 kg particle has a velocity of vx = 6.02 m/s and vy = 0.316 m/s.
Find the magnitude of its total momentum. Answer in units of kg · m/s

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asked by Kaylee
  1. First convert velocities to their resultant vector:
    v=sqrt(vx²+vy²)
    =6.03 m/s

    Momentum=mass*velocity
    = 2.73 kg * 6.03 m/s
    = 16.5 kg-m/s

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