The digit sum for 126 is 1+2+6, or 9. The digit sum for 300 is 3+0+0, 0r 3.
Find the two consecutive numbers that have digit sums of 36 and 1
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9,999 & 10,000
9 + 9 + 9 + 9 = 36
1 + 0 + 0 + 0 + 0 = 1
Same question need help
To find the two consecutive numbers that have digit sums of 36 and 1, we can start by understanding how to calculate the digit sum for a given number.
To find the digit sum of a number, we need to add up all the individual digits of the number. We repeat this process until we have a single-digit sum.
For example, to find the digit sum of 126, we add up 1 + 2 + 6, which equals 9.
To find the digit sum of 300, we add up 3 + 0 + 0, which gives us 3.
To find the consecutive numbers that have digit sums of 36 and 1, we can start with a number and check if its digit sum is equal to 36. If not, we move to the next number and continue this process until we find a number with the desired digit sum.
Let's start with the number 1 and calculate its digit sum.
The digit sum of 1 is 1 itself, which matches the desired digit sum of 1. Therefore, the number 1 is one of the consecutive numbers we are looking for.
To find the next consecutive number, we can increment the previous number by 1. So, the next number would be 1 + 1 = 2.
Now let's calculate the digit sum of 2. The digit sum of 2 is also 2, which does not match the desired digit sum of 36.
We need to continue this process by incrementing the number until we find a number with a digit sum of 36.
Let's try the number 3.
The digit sum of 3 is 3, which does not match the desired digit sum of 36.
We continue this process by incrementing the number. Let's try the number 4.
The digit sum of 4 is 4, which again does not match the desired digit sum of 36.
We continue incrementing the number and calculating the digit sum until we find a number that matches the desired digit sum.
Let's try the number 5.
The digit sum of 5 is 5, which is still not the desired digit sum of 36.
We continue incrementing the number and calculating digit sums until we find a match.
Let's try the number 6.
The digit sum of 6 is 6, which is not the desired digit sum of 36.
We continue this process until we find a number with a digit sum of 36.
After trying all the numbers up to 36, we see that none of them have a digit sum of 36.
Therefore, there are no two consecutive numbers that have digit sums of 36 and 1.
In this case, there is no solution, and the problem statement is impossible to fulfill.