# Algebra

(3+ sqrt18)/4 sqrt12

I'm not sure how to conjugate the denominator?

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1. repartir 152 entre A,B,C de modo que la parte de B sea 8 menos que el duplo de la de A y 32 mas que la de C

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posted by Aurora
2. (3+√18) / 4√12
= (3+3√2) / 8√3
= 3√3 (1+√2) / 24
= (1+√2)√3 / 8
= (√3+√6)/8

or several other ways to express it

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posted by Steve
3. B = 2A-8
B = C+32
A+B+C = 152

C = B-32 = 2A-8-32

A + 2A-8 + 2A-40 = 152
5A - 48 = 152
5A = 200
A=40
B=72
C=40

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posted by Steve

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