algebra

I need help solving this equation. 7y+5/3 = -8/y-3. I am stuck. please help me.

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asked by Maria
  1. I will assume the usual carelessness with parentheses, and that you mean

    (7y+5)/3 = -8/(y-3)

    Clear fractions (assuming y≠3) and we have

    (7y+5)(y-3) = -8(3)
    7y^2 - 16y - 15 = -24
    7y^2 - 16y + 9 = 0
    (7y-9)(y-1) = 0
    y = 1 or 9/7

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    posted by Steve

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