# Derivatives

Find the derivative of xsecy+y^5=5x^3-7

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1. x secy + y^5 = 5x^3 - 7
secy + x secy tany y' + 5y^4 y' = 15x^2
(x secy tany + 5y^4)y' = 15x^2 - secy

So,

y' =

15x^2 - secy
----------------------------
x secy tany + 5y^4

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posted by Steve

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