a rectangle's width is one-fifth its length, its perimeter is 60m. find the dimensions of the rectangle
Let's assume the length of the rectangle is L.
According to the given information, the width of the rectangle is one-fifth its length. Therefore, the width can be expressed as W = (1/5) * L.
The formula for the perimeter of a rectangle is: P = 2L + 2W.
Substituting the values, we get: 60 = 2L + 2((1/5) * L)
Simplifying the equation, we get: 60 = 2L + (2/5) * L
Combining like terms, we get: 60 = (12/5) * L
Multiplying both sides by 5/12 to isolate L, we get: L = (60 * 5) / 12
L = 300 / 12
L = 25
Therefore, the length of the rectangle is 25 meters.
Next, we can calculate the width using the equation W = (1/5) * L.
W = (1/5) * 25
W = 5
Therefore, the dimensions of the rectangle are 25 meters by 5 meters.
To find the dimensions of the rectangle, we can set up the problem using algebra.
Let's assume that the length of the rectangle is "L" meters. Since the width is one-fifth of the length, we can say that the width is "W" meters, where W = 1/5 * L.
Now, we can use the given information that the perimeter of the rectangle is 60m. The perimeter of a rectangle is calculated by adding the lengths of all four sides. In this case, it can be expressed as:
Perimeter = 2 * (Length + Width)
Substituting the values for Length (L) and Width (W), we get:
60 = 2 * (L + (1/5 * L))
Now, let's simplify the equation:
60 = 2 * (L + (1/5 * L))
60 = 2 * (6/5) * L
60 = (12/5) * L
To isolate L, we can divide both sides by (12/5):
L = (60 * 5) / 12
L = 25
So, the length of the rectangle is 25 meters.
To find the width (W), we can substitute the value of L into the equation for W:
W = 1/5 * L
W = 1/5 * 25
W = 5
Therefore, the width of the rectangle is 5 meters.
In summary, the dimensions of the rectangle are:
Length = 25 meters
Width = 5 meters
P = 2L + 2W
60 = 2(5W) + 2W
60 = 12W
5 = W