I am five digit number greater than 60 000 but less than 70 000: my ones digit is 1 less than my ten thousands digit. All my digits are the same. The sum of my didits is 23.
How can the digits all be the same?
64445
To find the five-digit number that satisfies the given conditions, we can approach it step by step.
Step 1: The ones digit is 1 less than the ten thousands digit.
This means that the ten thousands digit must be either 2 or 3 because the ones digit cannot be 0.
Step 2: All the digits are the same, and the sum of the digits is 23.
Since all the digits are the same, we need to find a five-digit number where all the digits are the same and their sum is 23.
Let's check the possible values for the ten thousands digit:
If the ten thousands digit is 2, then the sum of all digits would be 2 + 2 + 2 + 2 + (2-1) = 9.
If the ten thousands digit is 3, then the sum of all digits would be 3 + 3 + 3 + 3 + (3-1) = 14.
Since the sum of the digits needs to be 23, we can conclude that the ten thousands digit must be 3.
Step 3: Find the remaining digits.
Now that we know the ten thousands digit is 3, we can distribute the remaining sum of 23 - 14 = 9 among the five digits equally. This means each digit will be equal to 9/5 = 1.8, but since digits can only be whole numbers, we can approximate it to 2.
Therefore, the five-digit number that satisfies all the given conditions is: 32,222.