the millions period has three different odd digits whose sum is 21. all the other digits are zeros. what is the number ?

thank you

From your data, it could be:

579,000,000
597,…
975,…
etc.

So it says millions period. So it should've 9 digits, the sum of the three digits is 21. So it could be 579. It says their remaining digits is zeros. So my answer is 579,000,000

the millions period has three different odd digits whose sum is 21. all the other digits are zeros. what is the number ?

To find the number that meets the given conditions, we know that it is a million-period number, which means it has six digits and ends with zeros. We are also told that the number has three odd digits whose sum is 21.

Let's break down our steps to find the number:

Step 1: Start with the six-digit number format (X, X, X, 0, 0, 0), where X represents the three odd digits that sum up to 21.
- Notice that we can rearrange the three odd digits in any order because order doesn't affect the value when the sum is the same.

Step 2: We need to find three odd digits that sum up to 21. The possible odd digits (1, 3, 5, 7, and 9) can be paired in different combinations to get 21.
- After evaluating all the possible combinations, we find that 9 + 7 + 5 = 21 is the only combination that works.

Step 3: Place the three odd digits (9, 7, 5) in any order to replace the Xs in the six-digit number format.
- One possible arrangement could be 9, 7, 5 in the first three positions.

Step 4: Fill the remaining positions with zeros, giving us the final number.
- The final number is 975,000.

Therefore, the number that meets the given conditions is 975,000.