the billions period has three different even digits whose sum is 12. each of the other places is occupied by 8. what is the number? thank you
To find the number that fits the given criteria, we can follow these steps:
1. First, we know that the three different even digits must have a sum of 12. Let's list all the possible even digits that could fit this condition: 2, 4, 6, and 8.
2. We need to find a combination of three even digits whose sum is 12. Let's try each possibility:
- 2 + 4 + 6 = 12 (sum is 12)
- 4 + 6 + 2 = 12 (sum is 12)
- 2 + 6 + 4 = 12 (sum is 12)
- 4 + 2 + 6 = 12 (sum is 12)
- 6 + 2 + 4 = 12 (sum is 12)
- 6 + 4 + 2 = 12 (sum is 12)
From these combinations, we see that the digits 2, 4, and 6 satisfy the given condition.
3. Next, we know that each of the remaining places in the billions period should be occupied by 8.
4. The number will be in the billions period, so we can place the digits in their respective places. The number will be 8,862,842,888.
Therefore, the number that satisfies the given conditions is 8,862,842,888.