the billions period has three different even digits whose sum is 12. each of the other places is occupied by 8. what is the number?
246,888,888,888
From your data, it could also be:
426,888,888,888
624,888,888,888
462,…
642,…
264,...
To find the number that satisfies the given conditions, we will work through the digits one by one.
First, let's determine the position of the digit that does not equal 8. We know that the sum of the three different even digits is 12. The only possible combinations of even digits that sum to 12 are (2, 4, 6), (2, 6, 4), (4, 2, 6), (4, 6, 2), (6, 2, 4), and (6, 4, 2).
Next, let's determine the location of the digit 8. Since the digit 8 occupies all the other places, there should be three 8s in the remaining places.
Now, we have all the digits and their respective locations. Let's construct the number:
1. We fill in the positions for the digits that are not 8. Based on the combinations above, we can use the arrangement (2, 4, 6).
2. We fill in the positions for the digit 8: 8_8_8.
3. Finally, we concatenate all the digits to form the number: 824688.
Therefore, the number that satisfies the given conditions is 824688.