pre cal

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

f(x) = x2 - 3 and g(x) = square root of quantity three plus x

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  1. I see a whole bunch of posts, but no indication of your attempts to solve them. I'll do one of them here:

    f(g) = g^2-3 = (√(3+x))^2 - 3 = 3+x-3 = x
    g(f) = √(f+3) = √(x^2-3+3) = √x^2 = x

    However, note that √x^2 is not necessarily x.

    If x = -3, √9 = 3, not -3!

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    posted by Steve

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