calculate the volume of 2.04 m al l oh 3 needed to neutralize 22.0 ml of 880m h2so4
Find your caps key and use it. m stands for molality; M stands for molarity. I assume M is what you want? And I doubt you mean 880 m or M.
3H2SO4 + 2Al(OH)3 ==> Al2(SO4)3 + 6H2O
mols H2SO4 = M x L = ?
Convert mols H2SO4 to mols Al using the coefficients in the balanced equation.
Then M Al(OH)3 = mols Al(OH)3/L Al(OH)3. You have mols and M, solve for L.