Physics I for College

a rope that makes an angle of 30 degrees with the horizontal drags a crate along the floor. what must be the tension in the rope if a horizontal force of 40N is needed to drag the crate? please help me. i really didn't understand what my professor told me. he speak so fast. even in my physics book. i can't understand all of the lectures on that topic. what is the formula for it. the topic is Trigonometry and Vectors.

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asked by Ian
  1. If a horizontal force of 40N is needed to pull the crate, and the rope is making 30° with the horizontal, then the horizontal component is
    T(cos(30°) where T is the tension in the rope.
    T(cos(30°))=40 N
    and you can then solve for T (unit is in N).

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  2. thank you

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    posted by Ian
  3. You're welcome ! :)

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