If the events A and B are disjoint, A Intersection B =0, P(B) = 0.17 and P(A U B)=0.55. Find P(A)
Use the relation:
P(A∪B)=P(A)+P(B)+P(A∩B)
and solve P(A)
Note:
∩ = & c a p ;
To find the probability of event A, we can use the formula:
P(A U B) = P(A) + P(B) - P(A Intersection B)
Given that P(A U B) = 0.55 and P(B) = 0.17, and that A and B are disjoint (meaning A Intersection B = 0), we can substitute the values in the formula:
0.55 = P(A) + 0.17 - 0
Since A Intersection B = 0, the expression becomes:
0.55 = P(A) + 0.17
We can rearrange the equation to solve for P(A):
P(A) = 0.55 - 0.17
P(A) = 0.38
Therefore, the probability of event A is 0.38.