The equation for the reaction of sucrose(sugar)with oxygen is C12H22O11+12O2--->12CO2+11H2O

how many g of co2 is produced per g of sucrose used?how many mol of oxygen gas is needed to react with 1.0g sucrose?(C12H22O11=342g/mol)

Dear akhmal,

mol of sucrose used=
1/(12x12 + 22 + 11X16)
= 2.92x10^-3
as 1 mole of sucrose will produce 12 moles of Co2
mol of CO2 produced= (2.92x10^-3)X 12
= 0.035
grams of CO2 produced = 0.035 X (12+32)
= 1.54g

as 1 mole of sucrose will react with 12 moles of o2
mole of O2 needed= (2.92x10^-3)X 12
= 0.035087719

To find out how many grams of CO2 are produced per gram of sucrose used, we need to determine the molar ratio between sucrose and CO2.

First, let's calculate the molar mass of CO2:
C = 12.01 g/mol
O = 16.00 g/mol (x 2 since there are two oxygen atoms)
Molar mass of CO2 = 12.01 g/mol + 16.00 g/mol x 2 = 44.01 g/mol

The molar ratio between sucrose and CO2 is 1:12. This means that for every 1 mole of sucrose used, 12 moles of CO2 are produced. Since we know the molar mass of sucrose is 342 g/mol, we can calculate the molar mass of CO2 produced per mole of sucrose:

Molar mass of CO2 per mole of sucrose = Molar mass of CO2 x (1/12) = 44.01 g/mol x (1/12) = 3.67 g/mol

Therefore, for every 1 gram of sucrose used, approximately 3.67 grams of CO2 are produced.

Now let's calculate the number of moles of oxygen gas needed to react with 1.0 gram of sucrose:

Molar mass of sucrose = 342 g/mol
Mass of sucrose = 1.0 g

Number of moles of sucrose = Mass of sucrose / Molar mass of sucrose = 1.0 g / 342 g/mol ≈ 0.00292 mol

According to the balanced equation, the mole ratio between the oxygen and sucrose is 12:1. This means that for every 12 moles of O2, 1 mole of sucrose is needed.

Number of moles of oxygen = Number of moles of sucrose x (12/1) = 0.00292 mol x 12 = 0.03504 mol

Therefore, approximately 0.03504 moles of oxygen gas are needed to react with 1.0 gram of sucrose.

To determine how many grams of CO2 are produced per gram of sucrose used, we need to calculate the molar mass of CO2 and compare it to the molar mass of sucrose.

The molar mass of CO2 is 12.01 g/mol for carbon + (2 * 16.00 g/mol for oxygen) = 44.01 g/mol.

The molar mass of sucrose (C12H22O11) is 12 * 12.01 g/mol for carbon + 22 * 1.01 g/mol for hydrogen + 11 * 16.00 g/mol for oxygen = 342.34 g/mol.

Next, we'll find the ratio of the molar masses of CO2 to sucrose by dividing the molar mass of CO2 by the molar mass of sucrose:

44.01 g/mol / 342.34 g/mol ≈ 0.1284 mol CO2 / 1 mol sucrose.

Therefore, for each mole of sucrose used in the reaction, approximately 0.1284 moles of CO2 are produced. Now, let's proceed to calculate the number of grams of CO2 produced per gram of sucrose:

0.1284 mol CO2 / 1 mol sucrose × 44.01 g CO2 / 1 mol CO2 = 5.65 g CO2 / 1 g sucrose.

Hence, approximately 5.65 grams of CO2 are produced per gram of sucrose used.

Moving on to the second part of the question, we need to determine the number of moles of oxygen gas required to react with 1.0 gram of sucrose.

First, we calculate the number of moles of sucrose in 1.0 gram by using its molar mass:

1.0 g / 342.34 g/mol = 0.00292 mol sucrose.

Since the balanced chemical equation states that 12 moles of oxygen gas react with 1 mol of sucrose, we can set up the following ratio:

12 mol O2 / 1 mol sucrose = x mol O2 / 0.00292 mol sucrose.

Solving for x, we find:

x ≈ 0.00292 mol sucrose * 12 mol O2 / 1 mol sucrose ≈ 0.035 mol O2.

Therefore, approximately 0.035 moles of oxygen gas are needed to react with 1.0 gram of sucrose.

a. What is 12*44/molmasssugar

b. mole )2= molessugar*12