physics

a stone is projected upward with a speed of 80.0ft/s from a 224 ft tower. find the maximum height and the speed at which it strikes the ground.

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asked by roger
  1. Assuming no air resistance, and PE at bottom of tower to be zero, then
    At the maximum height,
    mgh=(224mg+m(80²)/2
    h=224+80²/(2g) [assume g=32.2 '/s²
    =224'+99.38'
    =323.38'

    At bottom of tower,
    mv²/2 = m(80²)/2+mg(224)
    solve for v to get
    v=144.31 '/s

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