physics

a stone is thrown straight upward and rises to a maximum vertical height of 40.0m. with what velocity was it thrown and how long does it take for the stone to return to the initial level from which it was thrown?

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asked by roger
  1. Ignore air resistance => no energy loss

    PE at 40.0 m = mgh = 40*9.8m J
    =392 J
    PE=KE=(1/2)mv²
    vi=sqrt(2gh)=sqrt(2*9.8*40)
    = 28 m/s

    Time = 2 * time it takes to reach highest point
    = 2*(28/9.8)
    = 5.71 s

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