# probability

90%of a countrys population are a right handed . what is the probability that exactly 29 people in a group of 30 are right handad?

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1. Binomial distribution
p(success) = .9
1-p = .1

P(29 out of 30)

= C(30,29) * .9^29 * .1^1

C(30,29) = 30! / [ 1! (29!) ]
= 30
so
30 * .9^29 * .1 = .1413

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posted by Damon

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