probability

90%of a countrys population are a right handed . what is the probability that exactly 29 people in a group of 30 are right handad?

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asked by Elin
  1. Binomial distribution
    p(success) = .9
    1-p = .1

    P(29 out of 30)

    = C(30,29) * .9^29 * .1^1

    C(30,29) = 30! / [ 1! (29!) ]
    = 30
    so
    30 * .9^29 * .1 = .1413

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    posted by Damon

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