What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl
78.7% according to e2020
no
Answers for CA Limiting Reactant and Percent Yeild:
B
A
D
C
D
D
B
To calculate the percent yield of NaCl, we need to compare the actual yield (21.2 g) to the theoretical yield.
Step 1: Write and balance the chemical equation:
CuCl2 + 2NaNO3 → 2NaCl + Cu(NO3)2
Step 2: Calculate the molar mass of CuCl2:
Cu = 63.55 g/mol
Cl = 35.45 g/mol x 2 = 70.90 g/mol
Molar mass of CuCl2 = 63.55 + 70.90 = 134.45 g/mol
Step 3: Convert the given mass of CuCl2 to moles:
Moles of CuCl2 = 31.0 g / 134.45 g/mol = 0.2307 mol (rounded to four decimal places)
Step 4: Use the stoichiometry of the balanced equation to find the theoretical yield of NaCl:
From the balanced equation, we see that 1 mole of CuCl2 reacts to produce 2 moles of NaCl.
Therefore, moles of NaCl = 2 * moles of CuCl2 = 2 * 0.2307 mol = 0.4614 mol (rounded to four decimal places)
Step 5: Calculate the molar mass of NaCl:
Na = 22.99 g/mol
Cl = 35.45 g/mol
Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mol
Step 6: Convert the moles of NaCl to grams:
Mass of NaCl = moles of NaCl * molar mass of NaCl = 0.4614 mol * 58.44 g/mol = 26.94 g (rounded to two decimal places)
Step 7: Calculate the percent yield:
Percent yield = (actual yield / theoretical yield) * 100
Percent yield = (21.2 g / 26.94 g) * 100 = 78.7% (rounded to one decimal place)
Therefore, the percent yield of NaCl is 78.7%.
write the balanced equation:
CuCl2 + 2NaNO3 >> Cu(NO3)2 + 2NaCl
so one mole of copper(II) chloride yields two moles of soduumchlorid.
how many moles of CuCL2 is 31 grams? Multiply that by two, and change that number of moles to grams NaCl
yield= 21.2/expected grams