Using 32.00 g/mole as the molecular mass of oxygen and 28.01 g/mole as the molecular mass of carbon monoxide, solve the above problem.

A)79.97
B)61.3
C)61.27
D)80.00

To solve the problem, we need to find the molecular mass of a compound when given the atomic masses of the elements present in it.

The molecular mass of carbon monoxide (CO) can be determined by adding the atomic masses of carbon (C) and oxygen (O). From the given information, we have:

Molecular mass of carbon (C) = 12.01 g/mole
Molecular mass of oxygen (O) = 32.00 g/mole

Molecular mass of carbon monoxide (CO) = Molecular mass of carbon (C) + Molecular mass of oxygen (O)
= 12.01 g/mole + 32.00 g/mole
= 44.01 g/mole

Therefore, the molecular mass of carbon monoxide is 44.01 g/mole.

Now, let's calculate the molecular mass of the compound using the given information.

Molecular mass of oxygen = 32.00 g/mole
Molecular mass of carbon monoxide = 28.01 g/mole

To calculate the molecular mass of the compound, we need to find the ratio of oxygen to carbon monoxide in the compound.

Molecular mass of the compound = (Molecular mass of oxygen × 2) + (Molecular mass of carbon monoxide × 3)
= (32.00 g/mole × 2) + (28.01 g/mole × 3)
= 64.00 g/mole + 84.03 g/mole
= 148.03 g/mole

Therefore, the molecular mass of the compound is 148.03 g/mole.

Comparing this result with the given options:
A) 79.97
B) 61.3
C) 61.27
D) 80.00

None of the options match the calculated molecular mass of 148.03 g/mole.

Hence, none of the given options are correct.