A number whose digit in the ten billions place is 5 less than 8

481,924,821,947,217,481,274,832,748,971,298

To find the number whose digit in the ten billions place is 5 less than 8, we need to determine the value of the digit in the ten billions place.

Since the digit in the ten billions place is 5 less than 8, it means it is 8 - 5 = 3.

Therefore, the number we are looking for has a digit 3 in the ten billions place.

To find the number whose digit in the ten billions place is 5 less than 8, we can start by recognizing that the ten billions place is the digit that represents a value that is 10 billion times larger than the digit to its right.

Given that the digit in the ten billions place is 5 less than 8, we subtract 5 from 8, which gives us 3. So, the digit in the ten billions place is 3.

To form the complete number, we can assign any value we want to the other places. Let's assume we assign 0 to all the other places.

Thus, the final number whose digit in the ten billions place is 5 less than 8 would be:
30,000,000,000 (thirty billion).