Find the probability of P(E or F) if E and F are mutually exclusive P(E)=0.25 and P(F)=0.47
what is .25(.47) ?
Please refer to your previous batch of questions.
An almost identical question was answered completely and explained.
that should be .25 + .47 for OR
the way I had it would have been for AND
To find the probability of P(E or F) when E and F are mutually exclusive, you can use the formula:
P(E or F) = P(E) + P(F)
Given that P(E) = 0.25 and P(F) = 0.47, you can substitute these values into the formula:
P(E or F) = 0.25 + 0.47
Now you can calculate the sum:
P(E or F) = 0.72
Therefore, the probability of P(E or F) when E and F are mutually exclusive is 0.72.