Chemistry

1. Nitric acid is produced via the following equation: 3 NO2 + H2O = 2HNO3 + NO. How many grams of NO2 are required to produce 7.5 grams of HNO3?

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asked by Brett
  1. Dear Brett,
    molar mass of the HNO3= 1+14+16x3
    =63

    number of moles of the HNO3 produced in the reaction = 7.5/63
    = 0.119

    According to the equation provided 3 moles of NO2 will produce 2 moles of HNO3
    Thus,number of moles of NO2 required=
    0.119/2x3
    = 0.179

    mass of N02 required=
    0.179x(14+32)
    = 8.214g

    Therefore, 8.214 grams of N02 is required

    Hope it helps:)

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    posted by Barry
  2. The answer should be 8.24 not 8.214

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    posted by Stef

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