Find the 12th term of the arithmetic sequence 2, 6, 10, … .
Just add 4 to the preceding number. Keep going til you reach the 12th term.
-2+(12-1)4=42
Ah, an arithmetic sequence! Let's see, to find the 12th term, we first need to find the common difference. And to find the common difference, we subtract the 2nd term from the 1st term.
So, 6 - 2 = 4.
Now, we can use the formula for an arithmetic sequence to find the 12th term:
An = A1 + (n - 1)d,
where A1 is the first term, n is the term we're looking for, and d is the common difference.
Plugging in the values:
A12 = 2 + (12 - 1) * 4.
A12 = 2 + 11 * 4.
A12 = 2 + 44.
A12 = 46.
So, the 12th term of the sequence is 46. But don't worry, it won't be as long as a clown's shoe!
To find the 12th term of an arithmetic sequence, we first need to identify the common difference (d) between consecutive terms. In an arithmetic sequence, each term can be obtained by adding the common difference to the previous term.
In the given sequence 2, 6, 10, … , we can observe that each term is obtained by adding 4 to the previous term. Hence, the common difference (d) is 4.
To find the 12th term, we can use the formula for the nth term of an arithmetic sequence:
an = a1 + (n - 1)d
where:
an = nth term
a1 = first term
d = common difference
n = position of the term
Substituting the values into the formula:
a12 = 2 + (12 - 1) * 4
= 2 + 11 * 4
= 2 + 44
= 46
Therefore, the 12th term of the arithmetic sequence 2, 6, 10, ... is 46.
a=2 ,d=4
term(12) = a+11d
= 2 + 44
= 46