Create an educational illustration of a physics scenario. Show a 3D perspective view of a laboratory setup with an inclined plane set at a thirty-degree angle to the flat horizontal table surface. On this slanted plane, place a solid cube representing an object with a mass of 50kg near the top. Depict the inclined plane's dimensions with a height of 250cm and a length of 500cm. Please ensure that the scene is detailed but includes no text.

An object of mass 50kg is placed on inclined plane at an angle of 30 degrees to the horizontal. The height of the plane is 250cm and it's length is 500cm. What is the workdone in moving the object down the plane?

F=mgcos@= 50*9.81*sin30= 424.8N

H=250cm= 2.5m
W=F*h = 424.8*2.5= 1062 J

F-mgsintheta=ma

Where F=force that tends to move it upward.
Mgsintheta= force that tends to move it downward.a=Acceleration
500-50×10sin30°=ma
500-250=50a
a=5m/s^2.
W=F×d=ma×d
50×5×500×10^-2
=50×5×5
=1250 Nm

assuming no friction, gravity does all the work and it is the change in potential energy

m g h = 50 * 9.81 * .250 Joules

I response

Please can some one help me to solve this assignment

W= f*s*cos 50*1250*0.9=56250

Mass 50kg

Degree 60
H=300cm=3m
L=100cm=1m
Work done (g=10m\s)
F=