Find the probability of P(E or F) if E and F are mutually exclusive P(E)=0.41 and P(F)=0.47
P(E∪F)=P(E)+P(F)-P(E∩F)
If E and F are mutually exclusive (ME), then P(E∩F)=0, and consequently
P(E∪F)=P(E)+P(F)=0.41+0.47=0.88
Well, since E and F are mutually exclusive, it means that they cannot occur at the same time. So, the probability of both E and F happening is zero.
To find the probability of E or F occurring, we simply add their individual probabilities together since they cannot happen simultaneously.
So, P(E or F) = P(E) + P(F) = 0.41 + 0.47 = 0.88.
So, the probability of E or F happening is 0.88. Just like a clown trying to balance on a unicycle, it's all about finding the right probabilities!
To find the probability of P(E or F) when E and F are mutually exclusive, we can use the formula:
P(E or F) = P(E) + P(F)
Since E and F are mutually exclusive events, they cannot occur at the same time. Therefore, the probability of both events occurring together is zero. Thus, P(E or F) = P(E) + P(F).
Given that P(E) = 0.41 and P(F) = 0.47, we can substitute these values into the formula to calculate:
P(E or F) = 0.41 + 0.47 = 0.88
Therefore, the probability of P(E or F) when E and F are mutually exclusive is 0.88.
To find the probability of P(E or F) when E and F are mutually exclusive, we need to know that mutually exclusive events cannot occur at the same time. Therefore, the probability of both events occurring simultaneously is 0.
We can calculate P(E or F) by summing the individual probabilities of E and F since they are mutually exclusive. The formula is:
P(E or F) = P(E) + P(F)
Given that P(E) = 0.41 and P(F) = 0.47, we can substitute these values into the formula:
P(E or F) = 0.41 + 0.47
= 0.88
So, the probability of P(E or F) is 0.88.