calculate the wt. of 6.022x 10^23 formula units of CaCO3
Look the atomic mass up on the periodic table and add them.
The answer is about 100.
To calculate the weight of a given number of formula units of a compound, you need to know the molar mass of the compound. In this case, the compound is CaCO3, which consists of one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).
To calculate the molar mass of CaCO3, you can add up the atomic masses of each element. The atomic masses of calcium, carbon, and oxygen are approximately 40.08 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively.
Molar mass of CaCO3 = (atomic mass of Ca) + (atomic mass of C) + 3 x (atomic mass of O)
Molar mass of CaCO3 = (40.08 g/mol) + (12.01 g/mol) + 3 x (16.00 g/mol)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
The molar mass of CaCO3 is 100.09 g/mol.
Next, you can use this molar mass to calculate the weight of 6.022 x 10^23 formula units of CaCO3.
Weight = (Number of formula units) x (Molar mass of CaCO3)
Weight = (6.022 x 10^23 formula units) x (100.09 g/mol)
Now, you can perform the calculation:
Weight = 6.022 x 10^23 x 100.09 g = 6.0256 x 10^25 g
Therefore, the weight of 6.022 x 10^23 formula units of CaCO3 is approximately 6.0256 x 10^25 grams.