# maths

If sin(theta)=3/5 , tan(phi)= 1/2 and 90¡ã< theta <180¡ã<phi< 270¡ã, find tha value of 8tan(theta) - 5^1/2 sec(phi)

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1. since θ is in QII
and Ø is in QIII,

tanθ = 3/-4
secØ = √5/-2

now go figure.

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posted by Steve

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