If sin(theta)=3/5 , tan(phi)= 1/2 and 90¡ã< theta <180¡ã<phi< 270¡ã, find tha value of 8tan(theta) - 5^1/2 sec(phi)

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asked by sumit
  1. since θ is in QII
    and Ø is in QIII,

    tanθ = 3/-4
    secØ = √5/-2

    now go figure.

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    posted by Steve

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