Math

1. Find the 12th term of the arithmetic sequence 2, 6, 10, … .

2. Solve for the 101st term of the sequence whose 1st term is x-y and d=2x+y-3.

3. In the sequence 2, 6, 10, … , what term has a value of 106?

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asked by Annika
  1. #1 and #2 are the same type as the ones I just did for you
    Give them a try

    #3
    a=2 , d=4

    a+(n-1)d = term(n)
    2 + (n-1)(4) = 106
    2 + 4n - 4 = 106
    4n = 108
    n = 27

    term(27) = 106

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    posted by Reiny
  2. Okay. I think I get it. Thanks for the help.

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    posted by Annika

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