Physics

A 0.020 rubber stopper is swung in a horizontal circle by 0.80 cm thread that makes 30.0 revolution every 20 seconds.

a.) what is the stopper's speed?

T=?
v=(2pi(r))/T

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asked by Roy
  1. T=1.5 s?

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    posted by Roy
  2. T (period)
    = time/rev
    = 20 sec/ 30 rev
    = 2/3 sec/rev

    ω(angular speed)
    =30 rev/20 seconds
    =30/20 rev / sec
    =30/20*2π radians / s

    Velocity
    =rω
    =0.008m*ω m/s

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