Bernardo divided one polynomial by another, as shown below.


(9x2-9x-10)/(3x+2)

What is the quotient?



A. 3x-1 + -8/3x+2

B. 3x-1 + -12/3x+2

C. 3x+5

D. 3x-5

nvm, i think i figured this one out :)

To find the quotient of the polynomial division, we need to divide the numerator (9x^2-9x-10) by the denominator (3x+2).

One way to do this is by using long division. Here's how you can approach it:

Step 1: Divide the first term of the numerator (9x^2) by the first term of the denominator (3x). This gives us 3x as the first term of the quotient.

Step 2: Multiply the divisor (3x+2) by the quotient term we just obtained (3x). (3x)*(3x+2) = 9x^2 + 6x.

Step 3: Subtract the result from step 2 from the numerator. (9x^2-9x-10) - (9x^2 + 6x) = -15x - 10.

Step 4: Bring down the next term from the numerator (-15x). We now have -15x - 10 as the new dividend.

Step 5: Repeat steps 1 to 4 until we have no more terms to bring down.

Step 6: Divide the new first term of the dividend (-15x) by the first term of the divisor (3x). This gives us -5 as the next term of the quotient.

Step 7: Multiply the divisor (3x+2) by the new quotient term (-5). (-5)*(3x+2) = -15x - 10.

Step 8: Subtract the result from step 7 from the current dividend (-15x - 10) - (-15x - 10) = 0.

Since our result is 0, we have no remainder.

The quotient we obtained is 3x - 5.

Therefore, the correct answer is option D: 3x - 5.